What is the integral from 0 to sqrt(x of)cos(12t) ?

The integral from 0 to sqrt(x of)cos(12t) is 1/12 sin(12sqrt(x))

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integral from 0 to sqrt(x of)cos(12t)

\int_{0}^{x} cos (12 t) d t

\frac{1}{12} sin (12 x)

Solution steps

\int_{0}^{x} cos (12 t) d t

Apply u-substitution

: \int_{0}^{12 x} cos (u) \frac{1}{12} d u

= \int_{0}^{12 x} cos (u) \frac{1}{12} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{12} \cdot \int_{0}^{12 x} cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= \frac{1}{12} [sin (u)]_{0}^{12 x}

Compute the boundaries:

sin (12 x)

= \frac{1}{12} sin (12 x)

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What is the integral from 0 to sqrt(x of)cos(12t) ?
The integral from 0 to sqrt(x of)cos(12t) is 1/12 sin(12sqrt(x))