What is the integral from-1 to 1 of-3x^2 ?

The integral from-1 to 1 of-3x^2 is -2

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integral from-1 to 1 of-3x^2

\int_{- 1}^{1} - 3 x^{2} d x

- 2

Solution steps

\int_{- 1}^{1} - 3 x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 3 \cdot \int_{- 1}^{1} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{- 1}^{1}

= - 3 [\frac{x ^{3}}{3}]_{- 1}^{1}

Compute the boundaries:

\frac{2}{3}

= - 3 \cdot \frac{2}{3}

Simplify

= - 2

\int_{0}^{x} sinh (3 t) d t

\int_{- 2}^{3} e^{\frac{- 4 x}{3}} d x

\int_{1}^{4} (\frac{x}{8} - \frac{3}{x}) d x

\int_{0}^{1} \frac{( - x + 1 ) ^{3}}{6} d x

\int_{1}^{3} h (x) d x

What is the integral from-1 to 1 of-3x^2 ?
The integral from-1 to 1 of-3x^2 is -2