What is the integral from 0 to 2 of (3x^2+2x+1) ?

The integral from 0 to 2 of (3x^2+2x+1) is 14

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 2 of (3x^2+2x+1)

\int_{0}^{2} (3 x^{2} + 2 x + 1) d x

14

Solution steps

\int_{0}^{2} 3 x^{2} + 2 x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} 3 x^{2} d x + \int_{0}^{2} 2 x d x + \int_{0}^{2} 1 d x

\int_{0}^{2} 3 x^{2} d x = 8

\int_{0}^{2} 2 x d x = 4

\int_{0}^{2} 1 d x = 2

= 8 + 4 + 2

Simplify

= 14

\int_{0}^{b} \frac{1}{x} d x

\int_{1}^{5} \frac{8}{x ^{3}} d x

\int_{0}^{x} cos (x^{2}) d x

\int_{0}^{2} \frac{sin ( π x )}{π x} d x

\int_{2}^{3} x (3 - x) d x

What is the integral from 0 to 2 of (3x^2+2x+1) ?
The integral from 0 to 2 of (3x^2+2x+1) is 14