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Popular >

integral from 0 to 1 of (2t+1)

Solution

\int_{0}^{1} (2 t + 1) d t

Solution

2

Solution steps

\int_{0}^{1} 2 t + 1 d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 2 t d t + \int_{0}^{1} 1 d t

\int_{0}^{1} 2 t d t = 1

\int_{0}^{1} 1 d t = 1

= 1 + 1

Simplify

= 2

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of (2t+1) ?
The integral from 0 to 1 of (2t+1) is 2