What is the integral from 1 to 6 of 2/(x^2) ?

The integral from 1 to 6 of 2/(x^2) is 5/3

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integral from 1 to 6 of 2/(x^2)

\int_{1}^{6} \frac{2}{x ^{2}} d x

\frac{5}{3}

Decimal

1.66666 \dots

Solution steps

\int_{1}^{6} \frac{2}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{1}^{6} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{1}^{6}

= 2 [- \frac{1}{x}]_{1}^{6}

Compute the boundaries:

\frac{5}{6}

= 2 \cdot \frac{5}{6}

Simplify

= \frac{5}{3}

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What is the integral from 1 to 6 of 2/(x^2) ?
The integral from 1 to 6 of 2/(x^2) is 5/3