What is the integral from 1 to 2 of (ln(x)) ?

The integral from 1 to 2 of (ln(x)) is 2ln(2)-1

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integral from 1 to 2 of (ln(x))

\int_{1}^{2} (ln (x)) d x

2 ln (2) - 1

Decimal

0.38629 \dots

Solution steps

\int_{1}^{2} ln (x) d x

Apply Integration By Parts

: [x ln (x) - \int 1 d x]_{1}^{2}

= [x ln (x) - \int 1 d x]_{1}^{2}

\int 1 d x = x

= [x ln (x) - x]_{1}^{2}

Compute the boundaries:

2 ln (2) - 1

= 2 ln (2) - 1

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What is the integral from 1 to 2 of (ln(x)) ?
The integral from 1 to 2 of (ln(x)) is 2ln(2)-1