What is the integral from 0 to 4+2i of z ?

The integral from 0 to 4+2i of z is ((2i+4)^2)/2

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integral from 0 to 4+2i of z

\int_{0}^{4 + 2 i} z d z

\frac{( 2 i + 4 ) ^{2}}{2}

Solution steps

\int_{0}^{4 + 2 i} z d z

Apply the Power Rule

: [\frac{z ^{2}}{2}]_{0}^{4 + 2 i}

= [\frac{z ^{2}}{2}]_{0}^{4 + 2 i}

Compute the boundaries:

\frac{( 2 i + 4 ) ^{2}}{2}

= \frac{( 2 i + 4 ) ^{2}}{2}

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What is the integral from 0 to 4+2i of z ?
The integral from 0 to 4+2i of z is ((2i+4)^2)/2