What is the integral from 1 to 6 of 8x^{-4} ?

The integral from 1 to 6 of 8x^{-4} is 215/81

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integral from 1 to 6 of 8x^{-4}

\int_{1}^{6} 8 x^{- 4} d x

\frac{215}{81}

Decimal Notation

2.65432 \dots

Solution steps

\int_{1}^{6} 8 x^{- 4} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 8 \cdot \int_{1}^{6} x^{- 4} d x

Apply the Power Rule

: [- \frac{1}{3 x ^{3}}]_{1}^{6}

= 8 [- \frac{1}{3 x ^{3}}]_{1}^{6}

Compute the boundaries:

\frac{215}{648}

= 8 \cdot \frac{215}{648}

Simplify

= \frac{215}{81}

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What is the integral from 1 to 6 of 8x^{-4} ?
The integral from 1 to 6 of 8x^{-4} is 215/81