What is the integral from-1 to 2 of 1/3 x^2 ?

The integral from-1 to 2 of 1/3 x^2 is 1

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integral from-1 to 2 of 1/3 x^2

\int_{- 1}^{2} \frac{1}{3} x^{2} d x

1

Solution steps

\int_{- 1}^{2} \frac{1}{3} x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int_{- 1}^{2} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{- 1}^{2}

= \frac{1}{3} [\frac{x ^{3}}{3}]_{- 1}^{2}

Compute the boundaries:

3

= \frac{1}{3} \cdot 3

Simplify

= 1

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What is the integral from-1 to 2 of 1/3 x^2 ?
The integral from-1 to 2 of 1/3 x^2 is 1