What is the integral from 0 to 2y of 1 ?

The integral from 0 to 2y of 1 is 2y

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integral from 0 to 2y of 1

\int_{0}^{2 y} 1 d x

2 y

Solution steps

\int_{0}^{2 y} 1 d x

Integral of a constant:

\int a d x = a x

= [1 \cdot x]_{0}^{2 y}

Simplify

= [x]_{0}^{2 y}

Compute the boundaries:

2 y

= 2 y

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\int_{3}^{6} \frac{6}{2 x - 3} d x

\int_{4}^{7} 28 - 11 x + x^{2} d x

\int_{- 3}^{3} 1 9 - x^{2} d x