What is the integral from 1 to 4 of 4/(x^3) ?

The integral from 1 to 4 of 4/(x^3) is 15/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 4 of 4/(x^3)

\int_{1}^{4} \frac{4}{x ^{3}} d x

\frac{15}{8}

Decimal Notation

1.875

Solution steps

\int_{1}^{4} \frac{4}{x ^{3}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int_{1}^{4} \frac{1}{x ^{3}} d x

Apply the Power Rule

: [- \frac{1}{2 x ^{2}}]_{1}^{4}

= 4 [- \frac{1}{2 x ^{2}}]_{1}^{4}

Compute the boundaries:

\frac{15}{32}

= 4 \cdot \frac{15}{32}

Simplify

= \frac{15}{8}

\int_{0}^{π} e^{- x} d x

\int_{2}^{x} cos (x) d x

\int_{5 x}^{x^{3}} e^{- t^{2}} d t

\int_{- 4}^{1} x^{3} + x^{2} - 10 x + 8 d x

\int_{- 1}^{27} x^{- \frac{1}{3}} d x

What is the integral from 1 to 4 of 4/(x^3) ?
The integral from 1 to 4 of 4/(x^3) is 15/8