What is the integral from-1 to 5 of (3x^2+4x) ?

The integral from-1 to 5 of (3x^2+4x) is 174

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integral from-1 to 5 of (3x^2+4x)

\int_{- 1}^{5} (3 x^{2} + 4 x) d x

174

Solution steps

\int_{- 1}^{5} 3 x^{2} + 4 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{5} 3 x^{2} d x + \int_{- 1}^{5} 4 x d x

\int_{- 1}^{5} 3 x^{2} d x = 126

\int_{- 1}^{5} 4 x d x = 48

= 126 + 48

Simplify

= 174

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What is the integral from-1 to 5 of (3x^2+4x) ?
The integral from-1 to 5 of (3x^2+4x) is 174