What is the integral from 0 to 1 of tan(pi)x ?

The integral from 0 to 1 of tan(pi)x is 0

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integral from 0 to 1 of tan(pi)x

\int_{0}^{1} tan (π) x d x

0

Solution steps

\int_{0}^{1} tan (π) x d x

tan (π) x = 0

= \int_{0}^{1} 0 d x

Integral of a constant:

\int a d x = a x

= [0 \cdot x]_{0}^{1}

Simplify

= [0]_{0}^{1}

Compute the boundaries:

0

= 0

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\int_{0}^{10} - 6 x^{2} - 12 x + 720 d x

\int_{0}^{2 π} (1 + sin (x))^{2} d x

\int_{0}^{1 + i} z^{2} d z

\int_{- 1}^{1} e^{x} \cdot x d x

What is the integral from 0 to 1 of tan(pi)x ?
The integral from 0 to 1 of tan(pi)x is 0