What is the integral from 0 to 50 of (10-0.2x) ?

The integral from 0 to 50 of (10-0.2x) is 250

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integral from 0 to 50 of (10-0.2x)

\int_{0}^{50} (10 - 0.2 x) d x

250

Solution steps

\int_{0}^{50} 10 - 0.2 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{50} 10 d x - \int_{0}^{50} 0.2 x d x

\int_{0}^{50} 10 d x = 500

\int_{0}^{50} 0.2 x d x = 250

= 500 - 250

Simplify

= 250

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What is the integral from 0 to 50 of (10-0.2x) ?
The integral from 0 to 50 of (10-0.2x) is 250