What is the integral from-7 to 1 of (-x^2-3x) ?

The integral from-7 to 1 of (-x^2-3x) is -128/3

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integral from-7 to 1 of (-x^2-3x)

\int_{- 7}^{1} (- x^{2} - 3 x) d x

- \frac{128}{3}

Decimal

- 42.66666 \dots

Solution steps

\int_{- 7}^{1} - x^{2} - 3 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{- 7}^{1} x^{2} d x - \int_{- 7}^{1} 3 x d x

\int_{- 7}^{1} x^{2} d x = \frac{344}{3}

\int_{- 7}^{1} 3 x d x = - 72

= - \frac{344}{3} - (- 72)

Simplify

- \frac{344}{3} - (- 72) : - \frac{128}{3}

= - \frac{128}{3}

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What is the integral from-7 to 1 of (-x^2-3x) ?
The integral from-7 to 1 of (-x^2-3x) is -128/3