What is the integral from-3 to 3 of (6e^{-6x}-6e^{6x})/((e^{-6x)+e^{6x})^2} ?

The integral from-3 to 3 of (6e^{-6x}-6e^{6x})/((e^{-6x)+e^{6x})^2} is 0

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integral from-3 to 3 of (6e^{-6x}-6e^{6x})/((e^{-6x)+e^{6x})^2}

\int_{- 3}^{3} \frac{6 e ^{- 6 x} - 6 e ^{6 x}}{( e ^{- 6 x} + e ^{6 x} ) ^{2}} d x

0

Solution steps

\int_{- 3}^{3} \frac{6 e ^{- 6 x} - 6 e ^{6 x}}{( e ^{- 6 x} + e ^{6 x} ) ^{2}} d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

\frac{6 e ^{- 6 x} - 6 e ^{6 x}}{( e ^{- 6 x} + e ^{6 x} ) ^{2}} :

Odd

= 0

\int_{- 1}^{x^{2}} (1 + x^{3})^{4} d x

\int_{0}^{1} π

\int_{0}^{2 π} 9 sin^{2} (t) d t

\int_{63}^{x} \frac{1}{30 ( 35 - x )} d x

\int_{1}^{9} \frac{1}{t} d t

What is the integral from-3 to 3 of (6e^{-6x}-6e^{6x})/((e^{-6x)+e^{6x})^2} ?
The integral from-3 to 3 of (6e^{-6x}-6e^{6x})/((e^{-6x)+e^{6x})^2} is 0