What is the integral from 1 to sqrt(x of+c)1 ?

The integral from 1 to sqrt(x of+c)1 is sqrt(x)+c-1

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integral from 1 to sqrt(x of+c)1

\int_{1}^{x + c} 1 d x

x + c - 1

Solution steps

\int_{1}^{x + c} 1 d x

Integral of a constant:

\int a d x = a x

= [1 \cdot x]_{1}^{x + c}

Simplify

= [x]_{1}^{x + c}

Compute the boundaries:

x + c - 1

= x + c - 1

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\int_{0}^{t} e^{- s t} d t

\int_{0}^{1} 4 x + e^{3 x} d x

What is the integral from 1 to sqrt(x of+c)1 ?
The integral from 1 to sqrt(x of+c)1 is sqrt(x)+c-1