en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 4 of 8x-32

Solution

\int_{0}^{4} 8 x - 32 d x

Solution

- 64

Solution steps

\int_{0}^{4} 8 x - 32 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} 8 x d x - \int_{0}^{4} 32 d x

\int_{0}^{4} 8 x d x = 64

\int_{0}^{4} 32 d x = 128

= 64 - 128

Simplify

= - 64

Graph

Popular Examples

integral from-pi to pi of-sin(x)

\int_{- π}^{π} - sin (x) d x

integral from 0 to 8 of (-x^2+8x)

\int_{0}^{8} (- x^{2} + 8 x) d x

integral from 0 to x of (x^2+1)

\int_{0}^{x} (x^{2} + 1) d x

integral from 1 to 5 of sqrt(9x-4)

\int_{1}^{5} 9 x - 4 d x

integral from 0 to 2pi of ((pi-x)/2)

\int_{0}^{2 π} (\frac{π - x}{2}) d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 4 of 8x-32 ?
The integral from 0 to 4 of 8x-32 is -64