What is the integral from 2 to 4 of f(t) ?

The integral from 2 to 4 of f(t) is f*6

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integral from 2 to 4 of f(t)

\int_{2}^{4} f (t) d t

f \cdot 6

Solution steps

\int_{2}^{4} f t d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= f \cdot \int_{2}^{4} t d t

Apply the Power Rule

: [\frac{t ^{2}}{2}]_{2}^{4}

= f [\frac{t ^{2}}{2}]_{2}^{4}

Compute the boundaries:

6

= f \cdot 6

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\int_{x^{2}}^{2 x} 4 x y d y

What is the integral from 2 to 4 of f(t) ?
The integral from 2 to 4 of f(t) is f*6