What is the integral from 2 to 3 of-4/(x^2) ?

The integral from 2 to 3 of-4/(x^2) is -2/3

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integral from 2 to 3 of-4/(x^2)

\int_{2}^{3} - \frac{4}{x ^{2}} d x

- \frac{2}{3}

Decimal

- 0.66666 \dots

Solution steps

\int_{2}^{3} - \frac{4}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 4 \cdot \int_{2}^{3} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{2}^{3}

= - 4 [- \frac{1}{x}]_{2}^{3}

Compute the boundaries:

\frac{1}{6}

= - 4 \cdot \frac{1}{6}

Simplify

= - \frac{2}{3}

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What is the integral from 2 to 3 of-4/(x^2) ?
The integral from 2 to 3 of-4/(x^2) is -2/3