What is the integral from 1 to 2 of (2x+2/(x^2)) ?

The integral from 1 to 2 of (2x+2/(x^2)) is 4

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integral from 1 to 2 of (2x+2/(x^2))

\int_{1}^{2} (2 x + \frac{2}{x ^{2}}) d x

4

Solution steps

\int_{1}^{2} 2 x + \frac{2}{x ^{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 2 x d x + \int_{1}^{2} \frac{2}{x ^{2}} d x

\int_{1}^{2} 2 x d x = 3

\int_{1}^{2} \frac{2}{x ^{2}} d x = 1

= 3 + 1

Simplify

= 4

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What is the integral from 1 to 2 of (2x+2/(x^2)) ?
The integral from 1 to 2 of (2x+2/(x^2)) is 4