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Popular >

integral from 0 to 3 of (6-2x)

Solution

\int_{0}^{3} (6 - 2 x) d x

Solution

9

Solution steps

\int_{0}^{3} 6 - 2 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{3} 6 d x - \int_{0}^{3} 2 x d x

\int_{0}^{3} 6 d x = 18

\int_{0}^{3} 2 x d x = 9

= 18 - 9

Simplify

= 9

Graph

Popular Examples

integral from 0 to 1 of x^{1/3}-x^{1/2}

\int_{0}^{1} x^{\frac{1}{3}} - x^{\frac{1}{2}} d x

integral from 2 to 3 of (x+4)

\int_{2}^{3} (x + 4) d x

integral from-4 to 4 of (pi)

\int_{- 4}^{4} (π) d x

integral from 2 to 5 of (10x+12)^3

\int_{2}^{5} (10 x + 12)^{3} d x

integral from 5 to 8 of 8

\int_{5}^{8} 8 d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 3 of (6-2x) ?
The integral from 0 to 3 of (6-2x) is 9