What is the integral from 0 to 2pi of 1/6 ?

The integral from 0 to 2pi of 1/6 is pi/3

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integral from 0 to 2pi of 1/6

\int_{0}^{2 π} \frac{1}{6} d θ

\frac{π}{3}

Decimal

1.04719 \dots

Solution steps

\int_{0}^{2 π} \frac{1}{6} d θ

Integral of a constant:

\int a d x = a x

= [\frac{1}{6} θ]_{0}^{2 π}

Compute the boundaries:

\frac{π}{3}

= \frac{π}{3}

\int_{0}^{1} \frac{sin ( x )}{1 - x} d x

\int_{0}^{4} \frac{1}{3 x + 2} d x

\int_{- 0.5}^{3.5} x^{3} - 6 x^{2} + 8 x d x

\int_{3}^{3} e^{x^{2}} d x

\int_{1}^{6} 9 x^{- 4} d x

What is the integral from 0 to 2pi of 1/6 ?
The integral from 0 to 2pi of 1/6 is pi/3