What is the integral from 0 to 2 of (x^2+21x) ?

The integral from 0 to 2 of (x^2+21x) is 134/3

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integral from 0 to 2 of (x^2+21x)

\int_{0}^{2} (x^{2} + 21 x) d x

\frac{134}{3}

Decimal

44.66666 \dots

Solution steps

\int_{0}^{2} x^{2} + 21 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} x^{2} d x + \int_{0}^{2} 21 x d x

\int_{0}^{2} x^{2} d x = \frac{8}{3}

\int_{0}^{2} 21 x d x = 42

= \frac{8}{3} + 42

Simplify

\frac{8}{3} + 42 : \frac{134}{3}

= \frac{134}{3}

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What is the integral from 0 to 2 of (x^2+21x) ?
The integral from 0 to 2 of (x^2+21x) is 134/3