Solution
Solution
+1
Solution steps
Apply Integral Substitution
Take the constant out:
Use the common integral:
Compute the boundaries:
Popular Examples
integral from-infinity to 0 of 3^{8x}integral from 1 to 7 of eintegral from 0 to t^8 of sqrt(u)integral from 0 to 8.9 of 960te^{-st}integral from 0 to 1 of (1-x)x^2
Frequently Asked Questions (FAQ)
What is the integral from 0 to 4 of 1/(16x^2+9) ?
The integral from 0 to 4 of 1/(16x^2+9) is 1/12 arctan(16/3)