What is the integral from 2.6 to 3 of (2x)/9 ?

The integral from 2.6 to 3 of (2x)/9 is 0.24888…

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integral from 2.6 to 3 of (2x)/9

\int_{2.6}^{3} \frac{2 x}{9} d x

0.24888 \dots

Solution steps

\int_{2.6}^{3} \frac{2 x}{9} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{2}{9} \cdot \int_{2.6}^{3} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{2.6}^{3}

= \frac{2}{9} [\frac{x ^{2}}{2}]_{2.6}^{3}

Simplify

= 0.22222 \dots [0.5 x^{2}]_{2.6}^{3}

Compute the boundaries:

1.12

= 0.22222 \dots \cdot 1.12

Simplify

= 0.24888 \dots

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What is the integral from 2.6 to 3 of (2x)/9 ?
The integral from 2.6 to 3 of (2x)/9 is 0.24888…