What is the integral from e to-2x of 1 ?

The integral from e to-2x of 1 is -2x-e

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integral from e to-2x of 1

\int_{e}^{- 2 x} 1 d x

- 2 x - e

Solution steps

\int_{e}^{- 2 x} 1 d x

Integral of a constant:

\int a d x = a x

= [1 \cdot x]_{e}^{- 2 x}

Simplify

= [x]_{e}^{- 2 x}

Compute the boundaries:

- 2 x - e

= - 2 x - e

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\int_{1}^{2} (3 - x) - (\frac{2}{x}) d x

\int_{- 1}^{1} x^{\frac{3}{2}} d x

\int_{1}^{3} \frac{1}{t - 2} d t

\int_{1}^{4} \frac{8}{x ^{2}} d x

What is the integral from e to-2x of 1 ?
The integral from e to-2x of 1 is -2x-e