What is the integral from 1 to 5 of 3/(x^3) ?

The integral from 1 to 5 of 3/(x^3) is 36/25

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integral from 1 to 5 of 3/(x^3)

\int_{1}^{5} \frac{3}{x ^{3}} d x

\frac{36}{25}

Decimal

1.44

Solution steps

\int_{1}^{5} \frac{3}{x ^{3}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{1}^{5} \frac{1}{x ^{3}} d x

Apply the Power Rule

: [- \frac{1}{2 x ^{2}}]_{1}^{5}

= 3 [- \frac{1}{2 x ^{2}}]_{1}^{5}

Compute the boundaries:

\frac{12}{25}

= 3 \cdot \frac{12}{25}

Simplify

= \frac{36}{25}

\int_{- 1}^{2} - 2 x + 4 d x

\int_{- 5}^{5} 5 d x

\int_{5}^{2} x^{3} d x

\int_{- 1}^{1} (2 - 2 y^{2}) d y

\int_{0}^{π} cos (5 x) d x

What is the integral from 1 to 5 of 3/(x^3) ?
The integral from 1 to 5 of 3/(x^3) is 36/25