What is the integral from 1 to 9 of sqrt(t) ?

The integral from 1 to 9 of sqrt(t) is 52/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 9 of sqrt(t)

\int_{1}^{9} t d t

\frac{52}{3}

Decimal

17.33333 \dots

Solution steps

\int_{1}^{9} t d t

Apply the Power Rule

: [\frac{2}{3} t^{\frac{3}{2}}]_{1}^{9}

= [\frac{2}{3} t^{\frac{3}{2}}]_{1}^{9}

Compute the boundaries:

\frac{52}{3}

= \frac{52}{3}

\int_{0}^{π} - 4 sin (x) d x

\int_{- 6}^{- 2} (- x + 3) d x

\int_{1}^{2} x - 3 d x

\int_{0}^{\frac{3}{2} π} \frac{2}{9 + x ^{2}} d x

\int_{e}^{e^{2}} \frac{1}{x ln ^{2} ( x )} d x

What is the integral from 1 to 9 of sqrt(t) ?
The integral from 1 to 9 of sqrt(t) is 52/3