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Popular >

integral from 0 to 1 of (y-y^2)

Solution

\int_{0}^{1} (y - y^{2}) d y

Solution

\frac{1}{6}

+1

Decimal

0.16666 \dots

Solution steps

\int_{0}^{1} y - y^{2} d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} y d y - \int_{0}^{1} y^{2} d y

\int_{0}^{1} y d y = \frac{1}{2}

\int_{0}^{1} y^{2} d y = \frac{1}{3}

= \frac{1}{2} - \frac{1}{3}

Simplify

\frac{1}{2} - \frac{1}{3} : \frac{1}{6}

= \frac{1}{6}

Graph

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\int_{1}^{4} - x d x

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\int_{- \infty}^{2 t} e^{x} d x

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\int_{1}^{64} \frac{( 2 + 3 x )}{x} d x

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\int_{0}^{1} (x^{2} + 3 x + 1) d x

integral from-1 to 1 of cos^3(x)

\int_{- 1}^{1} cos^{3} (x) d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of (y-y^2) ?
The integral from 0 to 1 of (y-y^2) is 1/6