What is the integral from-1 to 4 of [x] ?

The integral from-1 to 4 of [x] is 15/2

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integral from-1 to 4 of [x]

\int_{- 1}^{4} [x] d x

\frac{15}{2}

Decimal

7.5

Solution steps

\int_{- 1}^{4} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{- 1}^{4}

= [\frac{x ^{2}}{2}]_{- 1}^{4}

Compute the boundaries:

\frac{15}{2}

= \frac{15}{2}

\int_{0}^{1} (e^{x} - e^{2 x - 1}) d x

\int_{0}^{1} 6 x 1 + x^{2} d x

\int_{2}^{5} - 3 x + 4 d x

\int_{0}^{1} y^{2} y d y

\int_{- 1}^{2} 3 x^{2} - 2 x d x

What is the integral from-1 to 4 of [x] ?
The integral from-1 to 4 of [x] is 15/2