What is the integral from-infinity to 1 of x/(x^2+1) ?

The integral from-infinity to 1 of x/(x^2+1) is diverges

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integral from-infinity to 1 of x/(x^2+1)

\int_{- \infty}^{1} \frac{x}{x ^{2} + 1} d x

diverges

Solution steps

\int_{- \infty}^{1} \frac{x}{x ^{2} + 1} d x

Compute the indefinite integral:

\int \frac{x}{x ^{2} + 1} d x = \frac{1}{2} ln x^{2} + 1 + C

Compute the boundaries:

\int_{- \infty}^{1} \frac{x}{x ^{2} + 1} d x =

diverges

= diverges

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\int_{1}^{2} x \frac{1}{2} x^{2} + 6 d x

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What is the integral from-infinity to 1 of x/(x^2+1) ?
The integral from-infinity to 1 of x/(x^2+1) is diverges