What is the integral from 20-3sqrt(16-2x) to 14 of 1 ?

The integral from 20-3sqrt(16-2x) to 14 of 1 is 3sqrt(-2x+16)-6

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integral from 20-3sqrt(16-2x) to 14 of 1

\int_{20 - 3 16 - 2 x}^{14} 1 d y

3 - 2 x + 16 - 6

Solution steps

\int_{20 - 3 16 - 2 x}^{14} 1 d y

Integral of a constant:

\int a d x = a x

= [1 \cdot y]_{20 - 3 16 - 2 x}^{14}

Simplify

= [y]_{20 - 3 16 - 2 x}^{14}

Compute the boundaries:

3 - 2 x + 16 - 6

= 3 - 2 x + 16 - 6

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What is the integral from 20-3sqrt(16-2x) to 14 of 1 ?
The integral from 20-3sqrt(16-2x) to 14 of 1 is 3sqrt(-2x+16)-6