What is the integral from 0 to pi/2 of cos(z) ?

The integral from 0 to pi/2 of cos(z) is 1

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integral from 0 to pi/2 of cos(z)

\int_{0}^{\frac{π}{2}} cos (z) d z

1

Solution steps

\int_{0}^{\frac{π}{2}} cos (z) d z

Use the common integral:

\int cos (z) d z = sin (z)

= [sin (z)]_{0}^{\frac{π}{2}}

Compute the boundaries:

1

= 1

\int_{3}^{6} 6 x d x

\int_{- \infty}^{0} e^{x} x d x

\int_{2}^{4} x^{3} + 1 d x

\int_{- 5}^{5} 3 x d x

\int_{25}^{x} \frac{1}{t} d t

What is the integral from 0 to pi/2 of cos(z) ?
The integral from 0 to pi/2 of cos(z) is 1