What is the integral from-3 to 3 of 12-x^2-x^2-6 ?

The integral from-3 to 3 of 12-x^2-x^2-6 is 0

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integral from-3 to 3 of 12-x^2-x^2-6

\int_{- 3}^{3} 12 - x^{2} - x^{2} - 6 d x

0

Solution steps

\int_{- 3}^{3} 12 - x^{2} - x^{2} - 6 d x

Simplify

= \int_{- 3}^{3} - 2 x^{2} + 6 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{- 3}^{3} 2 x^{2} d x + \int_{- 3}^{3} 6 d x

\int_{- 3}^{3} 2 x^{2} d x = 36

\int_{- 3}^{3} 6 d x = 36

= - 36 + 36

Simplify

= 0

\int_{\frac{8}{27}}^{1} \frac{( 28 x ^{\frac{4}{3}} - 26 x ^{\frac{1}{3}} )}{x ^{2}} d x

\int_{0}^{12} ∣ x - 6 ∣ d x

\int_{- 4}^{0} x^{3} + x^{2} - 6 x - 6 x d x

\int_{1}^{3} x^{2} + 3 x - 4 d x

\int_{1}^{7} 2 x d x

What is the integral from-3 to 3 of 12-x^2-x^2-6 ?
The integral from-3 to 3 of 12-x^2-x^2-6 is 0