What is the integral from 0 to x^2+y^2 of 1 ?

The integral from 0 to x^2+y^2 of 1 is x^2+y^2

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integral from 0 to x^2+y^2 of 1

\int_{0}^{x^{2} + y^{2}} 1 d z

x^{2} + y^{2}

Solution steps

\int_{0}^{x^{2} + y^{2}} 1 d z

Integral of a constant:

\int a d x = a x

= [1 \cdot z]_{0}^{x^{2} + y^{2}}

Simplify

= [z]_{0}^{x^{2} + y^{2}}

Compute the boundaries:

x^{2} + y^{2}

= x^{2} + y^{2}

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\int_{0}^{1} \frac{x}{( x + 1 ) ^{4}} d x

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What is the integral from 0 to x^2+y^2 of 1 ?
The integral from 0 to x^2+y^2 of 1 is x^2+y^2