What is the solution for (1+cos(x))(dy)/(dx)=(1+e^{-y})sin(x) ?

The solution for (1+cos(x))(dy)/(dx)=(1+e^{-y})sin(x) is y=ln((c_{1})/(1+cos(x))-1)

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(1+cos(x))(dy)/(dx)=(1+e^{-y})sin(x)

(1 + cos (x)) \frac{d y}{d x} = (1 + e^{- y}) sin (x)

y = ln (\frac{c _{1}}{1 + cos ( x )} - 1)

Solution steps

(1 + cos (x)) \frac{d y}{d x} = (1 + e^{- y}) sin (x)

Solve separable ODE:

y = ln (\frac{c _{1}}{1 + cos ( x )} - 1)

y = ln (\frac{c _{1}}{1 + cos ( x )} - 1)

y^{^{'}} + 2 x y = e^{x}

\int x^{2} + 9 d x

x \to - 6 lim (x + 1)

x \to - 1 lim (x + x^{2} + x^{3})

\int \frac{1}{y ^{2} 5 - y ^{2}} d y

What is the solution for (1+cos(x))(dy)/(dx)=(1+e^{-y})sin(x) ?
The solution for (1+cos(x))(dy)/(dx)=(1+e^{-y})sin(x) is y=ln((c_{1})/(1+cos(x))-1)