What is the integral from 1 to 3 of 1/9 x^2 ?

The integral from 1 to 3 of 1/9 x^2 is 26/27

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integral from 1 to 3 of 1/9 x^2

\int_{1}^{3} \frac{1}{9} x^{2} d x

\frac{26}{27}

Decimal

0.96296 \dots

Solution steps

\int_{1}^{3} \frac{1}{9} x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{9} \cdot \int_{1}^{3} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{1}^{3}

= \frac{1}{9} [\frac{x ^{3}}{3}]_{1}^{3}

Compute the boundaries:

\frac{26}{3}

= \frac{1}{9} \cdot \frac{26}{3}

Simplify

= \frac{26}{27}

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What is the integral from 1 to 3 of 1/9 x^2 ?
The integral from 1 to 3 of 1/9 x^2 is 26/27