What is the integral from n to n+1 of (cos(x))/x ?

The integral from n to n+1 of (cos(x))/x is \Ci(n+1)-\Ci(n)

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integral from n to n+1 of (cos(x))/x

\int_{n}^{n + 1} \frac{cos ( x )}{x} d x

Ci (n + 1) - Ci (n)

Solution steps

\int_{n}^{n + 1} \frac{cos ( x )}{x} d x

Use the nonelementary integral:

\int \frac{cos ( x )}{x} d x = Ci (x)

= [Ci (x)]_{n}^{n + 1}

Compute the boundaries:

Ci (n + 1) - Ci (n)

= Ci (n + 1) - Ci (n)

\int_{0}^{1} - 2 y + 1 d y

\int_{5}^{6} x d x

\int_{0}^{\frac{π}{4}} t^{2} sin (2 t) d t

\int_{- 2}^{2} 2 x - 4 d x

\int_{- 1}^{0} (x^{2}) d x

What is the integral from n to n+1 of (cos(x))/x ?
The integral from n to n+1 of (cos(x))/x is \Ci(n+1)-\Ci(n)