What is the integral from x to 5 of sin(t^2) ?

The integral from x to 5 of sin(t^2) is sqrt(pi/2)\S(sqrt(2/pi)*5)-sqrt(pi/2)\S(sqrt(2/pi)x)

Popular >

integral from x to 5 of sin(t^2)

\int_{x}^{5} sin (t^{2}) d t

\frac{π}{2} § (\frac{2}{π} \cdot 5) - \frac{π}{2} § (\frac{2}{π} x)

Solution steps

\int_{x}^{5} sin (t^{2}) d t

Use the nonelementary integral:

\int sin (x^{2}) d x = \frac{π}{2} § (\frac{2}{π} x)

= [\frac{π}{2} § (\frac{2}{π} t)]_{x}^{5}

Compute the boundaries:

\frac{π}{2} § (\frac{2}{π} \cdot 5) - \frac{π}{2} § (\frac{2}{π} x)

= \frac{π}{2} § (\frac{2}{π} \cdot 5) - \frac{π}{2} § (\frac{2}{π} x)

\int_{0}^{2} 1 + 0.5 sin (π x) d x

\int_{1}^{x} e^{t^{3}} d t

\int_{2}^{\frac{5}{2}} \frac{1}{1 - x ^{2}} d x

\int_{0}^{10} x e^{- \frac{x}{14}} d x

\int_{x^{4}}^{x^{5}} (- 4 x - 2)^{3} d x

What is the integral from x to 5 of sin(t^2) ?
The integral from x to 5 of sin(t^2) is sqrt(pi/2)\S(sqrt(2/pi)*5)-sqrt(pi/2)\S(sqrt(2/pi)x)