What is the integral from-2 to 0 of 11/6 x^3 ?

The integral from-2 to 0 of 11/6 x^3 is -22/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-2 to 0 of 11/6 x^3

\int_{- 2}^{0} \frac{11}{6} x^{3} d x

- \frac{22}{3}

Decimal

- 7.33333 \dots

Solution steps

\int_{- 2}^{0} \frac{11}{6} x^{3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{11}{6} \cdot \int_{- 2}^{0} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{- 2}^{0}

= \frac{11}{6} [\frac{x ^{4}}{4}]_{- 2}^{0}

Compute the boundaries:

- 4

= \frac{11}{6} (- 4)

Simplify

= - \frac{22}{3}

\int_{- 6}^{6} 64 - x^{2} d x

\int_{- 1}^{2} 2 ∣ x ∣ d x

\int_{0}^{2} 4 e^{4 x} d x

\int_{0}^{\frac{π}{2}} 5 e^{x} cos^{2} (x) d x

\int_{0}^{\infty} e^{- \frac{x}{a}} d x

What is the integral from-2 to 0 of 11/6 x^3 ?
The integral from-2 to 0 of 11/6 x^3 is -22/3