What is the integral from (-pi)/2 to pi/2 of 1 ?

The integral from (-pi)/2 to pi/2 of 1 is pi

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integral from (-pi)/2 to pi/2 of 1

\int_{\frac{- π}{2}}^{\frac{π}{2}} 1 d x

π

Decimal Notation

3.14159 \dots

Solution steps

\int_{\frac{- π}{2}}^{\frac{π}{2}} 1 d x

Integral of a constant:

\int a d x = a x

= [1 \cdot x]_{\frac{- π}{2}}^{\frac{π}{2}}

Simplify

= [x]_{- \frac{π}{2}}^{\frac{π}{2}}

Compute the boundaries:

π

= π

\int_{0}^{4} 2 + 6 x d x

\int_{0}^{4} \frac{x}{3} d x

\int_{- 3}^{2} \frac{6}{x ^{3}} d x

\int_{8}^{3} 1 d x

\int_{0}^{1} π (e - e^{x})^{2} d x

What is the integral from (-pi)/2 to pi/2 of 1 ?
The integral from (-pi)/2 to pi/2 of 1 is pi