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Popular >

integral from 3 to 4 of 6t-18

Solution

\int_{3}^{4} 6 t - 18 d t

Solution

3

Solution steps

\int_{3}^{4} 6 t - 18 d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{3}^{4} 6 t d t - \int_{3}^{4} 18 d t

\int_{3}^{4} 6 t d t = 21

\int_{3}^{4} 18 d t = 18

= 21 - 18

Simplify

= 3

Popular Examples

integral from-2 to 2 of xsqrt(x^2)

\int_{- 2}^{2} x x^{2} d x

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\int_{1}^{8} (x^{2} + 2) d x

integral from-1 to 1 of (15)/((x+2)^2)

\int_{- 1}^{1} \frac{15}{( x + 2 ) ^{2}} d x

integral from 3 to 1 of 5sqrt(x)

\int_{3}^{1} 5 x d x

integral from 1 to infinity of 1/((x+1))

\int_{1}^{\infty} \frac{1}{( x + 1 )} d x

Frequently Asked Questions (FAQ)

What is the integral from 3 to 4 of 6t-18 ?
The integral from 3 to 4 of 6t-18 is 3