What is the derivative of x^2+6x-3 ?

The derivative of x^2+6x-3 is 2x+6

What is the first derivative of x^2+6x-3 ?

The first derivative of x^2+6x-3 is 2x+6

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derivative of

x^{2} + 6 x - 3

2 x + 6

Solution steps

\frac{d}{d x} (x^{2} + 6 x - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (6 x) - \frac{d}{d x} (3)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (6 x) = 6

\frac{d}{d x} (3) = 0

= 2 x + 6 - 0

Simplify

= 2 x + 6

49 y^{^{''}} + 42 y^{^{'}} + 9 y = 0, y (0) = a, y^{^{'}} (0) = 2

x = \frac{( y - 3 ) ^{2}}{3}, y = 9 - x

7 x y \frac{d y}{d x} = 2

\frac{d}{d x} (1 + 5 x)

\frac{d}{d x} (\frac{x - 2}{x ^{2} + 4})

What is the derivative of x^2+6x-3 ?
The derivative of x^2+6x-3 is 2x+6
What is the first derivative of x^2+6x-3 ?
The first derivative of x^2+6x-3 is 2x+6