What is the integral from x to 1 of y ?

The integral from x to 1 of y is (1-x^2)/2

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integral from x to 1 of y

\int_{x}^{1} y d y

\frac{1 - x ^{2}}{2}

Solution steps

\int_{x}^{1} y d y

Apply the Power Rule

: [\frac{y ^{2}}{2}]_{x}^{1}

= [\frac{y ^{2}}{2}]_{x}^{1}

Compute the boundaries:

\frac{1}{2} - \frac{x ^{2}}{2}

= \frac{1}{2} - \frac{x ^{2}}{2}

Simplify

= \frac{1 - x ^{2}}{2}

\int_{- 5}^{1} \frac{1}{5 - 4 x} d x

\int_{- 2}^{1} x^{2} + 2 d x

\int_{- 2}^{2} 1 + (2 x)^{2} d x

\int_{3}^{9} (\frac{1}{x ^{2}}) d x

\int_{- 2}^{4} (x + 2) d x

What is the integral from x to 1 of y ?
The integral from x to 1 of y is (1-x^2)/2