What is the integral from 2 to 3 of (3x-2)/(x^3-x^2) ?

The integral from 2 to 3 of (3x-2)/(x^3-x^2) is 2ln(2)+1/3-ln(3)

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integral from 2 to 3 of (3x-2)/(x^3-x^2)

\int_{2}^{3} \frac{3 x - 2}{x ^{3} - x ^{2}} d x

2 ln (2) + \frac{1}{3} - ln (3)

Decimal Notation

0.62101 \dots

Solution steps

\int_{2}^{3} \frac{3 x - 2}{x ^{3} - x ^{2}} d x

Take the partial fraction of

\frac{3 x - 2}{x ^{3} - x ^{2}} : - \frac{1}{x} + \frac{2}{x ^{2}} + \frac{1}{x - 1}

= \int_{2}^{3} - \frac{1}{x} + \frac{2}{x ^{2}} + \frac{1}{x - 1} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{2}^{3} \frac{1}{x} d x + \int_{2}^{3} \frac{2}{x ^{2}} d x + \int_{2}^{3} \frac{1}{x - 1} d x

\int_{2}^{3} \frac{1}{x} d x = ln (3) - ln (2)

\int_{2}^{3} \frac{2}{x ^{2}} d x = \frac{1}{3}

\int_{2}^{3} \frac{1}{x - 1} d x = ln (2)

= - (ln (3) - ln (2)) + \frac{1}{3} + ln (2)

Simplify

= 2 ln (2) + \frac{1}{3} - ln (3)

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What is the integral from 2 to 3 of (3x-2)/(x^3-x^2) ?
The integral from 2 to 3 of (3x-2)/(x^3-x^2) is 2ln(2)+1/3-ln(3)