What is the integral from 0 to 1 of sin(θ) ?

The integral from 0 to 1 of sin(θ) is -cos(1)+1

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integral from 0 to 1 of sin(θ)

\int_{0}^{1} sin (θ) d θ

- cos (1) + 1

Decimal Notation

0.45969 \dots

Solution steps

\int_{0}^{1} sin (θ) d θ

Use the common integral:

\int sin (θ) d θ = - cos (θ)

= [- cos (θ)]_{0}^{1}

Compute the boundaries:

- cos (1) + 1

= - cos (1) + 1

\int_{- 1}^{0} x^{2} + x d x

\int_{0}^{\frac{π}{2}} sin (φ) d φ

\int_{0}^{1} (x^{2}) - (x) d x

\int_{- 3}^{2} (12 - x^{2} - x) d x

\int_{1}^{2.5} x d x

What is the integral from 0 to 1 of sin(θ) ?
The integral from 0 to 1 of sin(θ) is -cos(1)+1