What is the integral from 0 to 1 of x17^{x^2} ?

The integral from 0 to 1 of x17^{x^2} is 8/(ln(17))

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integral from 0 to 1 of x17^{x^2}

\int_{0}^{1} x 1 7^{x^{2}} d x

\frac{8}{ln ( 17 )}

Decimal Notation

2.82364 \dots

Solution steps

\int_{0}^{1} x \cdot 1 7^{x^{2}} d x

Apply u-substitution

: \int_{1}^{17} \frac{1}{2 ln ( 17 )} d u

= \int_{1}^{17} \frac{1}{2 ln ( 17 )} d u

Integral of a constant:

\int a d x = a x

= [\frac{1}{2 ln ( 17 )} u]_{1}^{17}

Compute the boundaries:

\frac{8}{ln ( 17 )}

= \frac{8}{ln ( 17 )}

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What is the integral from 0 to 1 of x17^{x^2} ?
The integral from 0 to 1 of x17^{x^2} is 8/(ln(17))