What is the integral from 0 to 4 of pi(x)^2 ?

The integral from 0 to 4 of pi(x)^2 is (64pi)/3

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integral from 0 to 4 of pi(x)^2

\int_{0}^{4} π (x)^{2} d x

\frac{64 π}{3}

Decimal Notation

67.02064 \dots

Solution steps

\int_{0}^{4} π x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= π \cdot \int_{0}^{4} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{0}^{4}

= π [\frac{x ^{3}}{3}]_{0}^{4}

Compute the boundaries:

\frac{64}{3}

= π \frac{64}{3}

Simplify

= \frac{64 π}{3}

\int_{0}^{x^{4}} e^{t} d t

\int_{3}^{4} x^{2} - 3 x d x

\int_{0}^{3} e^{- 3 x} d x

\int_{0}^{9} \frac{1}{( 1 + x ) ^{2}} d x

\int_{1}^{t} - 5 t + 9 d t

What is the integral from 0 to 4 of pi(x)^2 ?
The integral from 0 to 4 of pi(x)^2 is (64pi)/3