What is the integral from 1 to 4 of A/(7.5^2) ?

The integral from 1 to 4 of A/(7.5^2) is 0.13333…

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integral from 1 to 4 of A/(7.5^2)

\int_{1}^{4} \frac{A}{7. 5 ^{2}} d A

0.13333 \dots

Solution steps

\int_{1}^{4} \frac{A}{7. 5 ^{2}} d A

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{7. 5 ^{2}} \cdot \int_{1}^{4} A d A

Simplify

= 0.01777 \dots \cdot \int_{1}^{4} A d A

Apply the Power Rule

: [\frac{A ^{2}}{2}]_{1}^{4}

= 0.01777 \dots [\frac{A ^{2}}{2}]_{1}^{4}

Simplify

= 0.01777 \dots [0.5 A^{2}]_{1}^{4}

Compute the boundaries:

7.5

= 0.01777 \dots \cdot 7.5

Simplify

= 0.13333 \dots

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What is the integral from 1 to 4 of A/(7.5^2) ?
The integral from 1 to 4 of A/(7.5^2) is 0.13333…